what is the angle between A vector and the resultant of (A+2Bcap) and (2A-2Bcap)
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Answer:
R=a2+b2+2abcosθ
10A=(2A)2+2A2)+2(2A)(2A)cosθ
10A2=4A+2A2+42A2cosθ
10=6+42cosθ
cosθ=(424)=(21)
∴θ=(4π)
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