What is the angle
between (i+j) and (i- j)?
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The angle is 90 degree.
Given:
The two vectors, a = i + j and b = i - j
Solution:
To calculate the angle between them, we need to draw the vector diagram of both.
Drawing the vectors, we get the dot product of the two vector.
From the dot product rule, we get,
\cos \theta=\frac{\overline{a} \overline{b}}{|\overline{a}| \cdot|\overline{b}|}cosθ=
∣
a
∣⋅∣
b
∣
a
b
Where, \thetaθ be the angle between the two vector.
\overline{a} \overline{b}=(1 \times 1)+(1 \times(-1))=1-1=0
a
b
=(1×1)+(1×(−1))=1−1=0
\cos \theta=\frac{0}{|\overline{a}| \cdot|\overline{b}|}cosθ=
∣
a
∣⋅∣
b
∣
0
\therefore \cos \theta=0∴cosθ=0
On solving, we get,
\theta=\cos ^{-1} 0θ=cos
−1
0
\theta=90^{\circ}θ=90
∘
Thereby, \thetaθ is 90 degrees to be the angle between the two vectors.
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