what is the angle between i+j and i-j?
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draw both the vectors !
costheta = [(i+j).(i-j)]/ (magnitude of i+j).(magnitude of i-j)
i.e,costheta=0
theta = 90.
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costheta = [(i+j).(i-j)]/ (magnitude of i+j).(magnitude of i-j)
i.e,costheta=0
theta = 90.
#Mark as Brainliest.
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