what is the angle between the line x+y=1 and x-y=1?
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Answered by
3
y=1-x (y=mx+c) slope is -1 m1=-1
y=x-1 m2=1
angle between lines= tan z= |m1+m2/1-m1m2|
tanz= 1-1/1+1=0/2
hence z = tan inverse 0=0 degree
y=x-1 m2=1
angle between lines= tan z= |m1+m2/1-m1m2|
tanz= 1-1/1+1=0/2
hence z = tan inverse 0=0 degree
Answered by
3
we knw that line equ. is
y=mx+c,
after comparisn those lines, here is
m1=-1, m2=1
than angle
tanz=m1+m2/1-m1m2
tanz=0,
z=0
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