Question

what is the angle between vector A =5icap - 5jcap and vector B =7/2i-7/2jcap​

Answer 1

Answer:

Angle between A and B is 0°

Explanation:

A . B = ABcos¢

Now, A . B is

(5i-5j) .(7/2i-7/2j)=35

Now,

35=5root2*7/root 2 cos¢

Therefore, cos¢=1

Or, ¢=0°

Answer 2

Answer:

vector A=I - 5j cap & vector B=2i cap-10jcap

COs theta =  Vector A . Vector B / AB

= 2+50 / root 26 . root 104

= 52/ Root 26 . 2 root 26

= 52 / 26 root 2

my friends therefore , Our theta is equal to or value of theta is

theta = 90 degrees

Explanation: