Question

what is the angle between vector a and vector b ​

Answer 1

Answer:

$\alpha = \frac{\pi}{4}$

Step-by-step explanation:

$Given \: it \: \\ |a| = 1 \: \: |b| = 1 \\ let \: the \: between \: a \: and \: b = \alpha \\ according \: to \: the \: question \\ | \sqrt{2} a - b| = 1 \\ { | \sqrt{2} a - b| }^{2} = 1 \\ 2 { |a| }^{2} + { |b| }^{2} - 2 \sqrt{2} |a| |b| cos \alpha = 1 \\ 2 + 1 - 2 \sqrt{2} cos \alpha = 1 \\ 2 \sqrt{2} cos \alpha = 2 \\ cos \alpha = \frac{1}{ \sqrt{2} } \\ \alpha = \frac{\pi}{4} \\ \\ \\ \\ \\ hope \: it \: will \: help \: you.....$