Question

what is the angle between velocity and acceleration if v=(3i-4j+2k) m/sec and a=(2i+j-2k)?
​

Answer 1

Step-by-step explanation:

Its a question of physics so read the topic Cartesian coordinates system u will get answer from here

Answer 2

Answer:

We know cosθ =

v×a

v.a

-----(1)

v.a=−2

∣v∣=

3

2

+(−4)

2

+(2)

2

=

29

∣a∣=

2

2

+(1)

2

+(−2)

2

=3

Putting the found values in (1), we get

cosθ=

∣v∣×∣a∣

v.a

=

3

9

−2

θ=cos

−1

(

3

9

−2

)=97.11

Thus the angle between v and a is obtuse .