Question

What is the angle made by vector of a =2i +2j with x axis?

Answer 1

Heya Friend !!

Please view the solution in the attachment .

hope this helps :)

Answer 2

Answer:

The required angle is 45°.

Step-by-step explanation:

To find : What is the angle made by vector of $\vec{a}=2i +2j$ with x axis?  

Solution :

The formula to fin the angle between vector and x-axis,

$\cos\theta=\frac{A_x}{\sqrt{A_x^2+A_y^2+A_z^2}}$

Here, $A_x=2,A_y=2,A_z=0$

Substitute in the formula,

$\cos\theta=\frac{2}{\sqrt{2^2+2^2+0^2}}$

$\cos\theta=\frac{2}{\sqrt{4+4+0}}$

$\cos\theta=\frac{2}{\sqrt{8}}$

$\cos\theta=\frac{2}{2\sqrt{2}}$

$\cos\theta=\frac{1}{\sqrt{2}}$

$\cos\theta=cos(45)$

$\theta=45^\circ$

Therefore, The required angle is 45°.