Question

what is the angle of elevation of a 15 m high tower from a point 15 m away from its foot

Answer 1

the value of theta is 45 degree.




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thanks

Answer 2

perp = 15m.
base = 15m.
$\tan( \theta) = \frac{perp}{base}$
$\theta \: = {tan}^{ - 1} \frac{15}{15} \\ \theta = {tan}^{ - 1} 1 \\ \theta \: = {45}^{0}$