Question

what is the angle of elevation of the sun,if the length of the shadow of a tower is 1/√3 times the height of the tower?
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Answer 1

Answer:

$\displaystyle\huge\red{\underline{\underline{AnSWeR}}}$

Let height of tower (AB) be h metres

Then length of its shadow will be

$BC= \frac{1}{ \sqrt{3} } h \: \: metres$

Let angle of elevation be θ

Now, In △ABC

$tanθ = \frac{p}{b} = \frac{AB}{BC</p><p>} \\ tanθ = \frac{h}{ \frac{1}{ \sqrt{3}h } } = \sqrt{3}$

⇒θ=60°

Answer 2

Answer:

1/√3=

ten 30

angel=30°

Step-by-step explanation:

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