Question

what is the angle of elevation of the sun when the length of shadow of a 16 root 3 high pole is 48 m

Answer 1

Let angle of elevation of sun be ß
So , tanß = 16√3/48
tanß = tan30°
ß = 30°

Answer 2

Given:

• Length of the shadow = 16√3
• Height of the pole, h = 48 m

To Find:

• The angle of elevation.

Solution:

• Let the angle of elevation be θ
• We have a formula for angle of elevation saying,
• tanθ = height of pole/length of the shadow of the sun
• tanθ = H/S
• Substitute the values in the above formula we get,
• tanθ = 48/16√3 = 3/√3
• tanθ = √3
• The angle of elevation of the sun, θ = $tan^{-1}$ √3 = 60°

∴ The angle of elevation = 60°.