What is the angle of elevation when the height of pole is equal to shadow of pole
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We can write 10x/y^2 Log 10x-2 logy We know log 10 =1 So 1+(m+n) - 2(m-n) Then the answers will be 1-m+3n
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Let, height of pole be h and shadow of pole be x .
Let , the angle of elevation be A.
but x=h
tanA=height of pole/shadow of pole
TanA=h/x
TanA=1
but, 1=tan45°
thus,angle of elevation is 45°
Let , the angle of elevation be A.
but x=h
tanA=height of pole/shadow of pole
TanA=h/x
TanA=1
but, 1=tan45°
thus,angle of elevation is 45°
satakchikashiv:
Right
thnku
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