What is the angle of inclination (0) and friction if a weight of 150 kg is in equilibrium
(coefficient of friction is 0.25)?
a) 0 = 14° 2V
F=37.50 kg
b) 0 = 14° 25
F = 37.50 kg
c) 0 = 12° 2
F=37.50 kg
d) 0 = 14° 2'
F = 36.50 kg
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