Question

What is the angle of inclination if a weight
of 150 kg is in equilibrium and the value of mis
0.5773?​

Answer 1

Answer:

30° - answer

Step-by-step explanation:

30° is the angle of inclination if a weight  of 150 kg is in equilibrium and the value of m is  0.5773.

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Answer 2

$30^{0}$

Explanation:

• We know that   $m = tan(\theta)$

• this means  $0.5773 = tan (\theta)$

• therefore  $\theta = tan^{-1}(0.5773)$
• value of $tan^{-1}(0.5773)$ is $30^0$
• Therefore the angle of inclination must be 30 degrees