English, asked by arunss718, 28 days ago

What is the angle of inclination if a weight of 150 kg is in equilibrium and the value of m is 0.0125?

Answers

Answered by poyumjangnyopoyumjan

1

Answer:

Tan 0=u = 0.25 0 =14.1° Normal force N= mg cos 14.1° N= 150*9.8 cos 14.1° = 1425. 7N.

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