Question

What is the angle of inclination if a weight
of 150 kg is in equilibrium and the value of m is
0.5773?

Answer 1

Answer:

The weight is in equilibrium on an inclined plane. Therefore, the inclination of the plane, must be equal to the angle of repose. Given μ=0.25 μ=0.25

Angle of Inclination θ θ =Angle of repose λ=tan−1(μ)=140 λ=tan−1⁡(μ)=140

Normal reaction= Wcosθ=150×9.8×cos(140)=1426NWcos⁡θ=150×9.8×cos⁡(140)=1426N

Answer 2

Answer:

Delhi and Ajmer were the two cities under control of the Chahamanas.