Question

what is the angle of projection for maximum height for a given velocity in projectile motion
answer me quick​

Answer 1

Answer:

Call the maximum height y = h. Then, h=v20y2g. This equation defines the maximum height of a projectile above its launch position and it depends only on the vertical component of the initial velocity

Explanation:

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Answer 2

Answer:-

✏ As the angle of projection is always acute it can take only + one value.Thus for a given velocity of projection, the horizontal range in maximum when the angle of projection is 45°.Thus for a given velocity of a projection, the maximum range of projection is 4 time the maximum height reached by it.

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