Question

What is the angle of projection of an oblique projectile if its range is √3v^2/2g?
a) 60° b) 150 c) 30° d) 90°​

Answer 1

Answer:

given = range = R=$\sqrt{3v^{2} }$/2g  

to find = angle of projection.

solution,

we know that,

       range  = R = v²sin2θ /g

∴ R=$\sqrt{3v^{2} }$/2g  = v²sin2θ /g  

∴sin2θ = $\sqrt{3}$/2

∴sin60° = $\sqrt{3}$/2 ...

∴2θ = 60°

so,θ = 30° also we can write this

∴as 90 - θ = 60°

∴therefor the option A and C can be correct answers.

∴the range of oblique projectile is can be 30° or  60°

Answer 2

Answer:

Answer to thik diya kro 30 ya 60 kya hota h