Question

What is the angle of projection of projectile for wjich is max hight nd horizontal ranges are equal?

Answer 1

The horizontal component of the velocity does not change. If the angle of projection is 75.96 degrees the maximum height is equal to the horizontal range.

Answer 2

R be range and H be height

R= u²sin2θ/g

H= u²sin²θ/2g

Since R=H;

u²sin2θ/g = u²sin²θ/2g

2 sin2θ = sin²θ

2*2sinθcosθ = sin²θ

4 = tanθ

.'. θ = tan^-1(4)

= 75.96° or ~ 76°