Question

What is the angle of projection to have a maximum range in kitti pull

Answer 1

The maximum angle of the Projection for having the maximum range is 45°.  

Reason ⇒ As we all know that the maximum m value of the Sine is 1 which is on 90°.

∴ From the Formula of Range,

R = u²Sin2θ/g, we must need to multiply 2 by 45° to get 90°. This can give the maximum angle for maximum range. Initial velocity can also increase to give maximum range.

Hope it helps.