What is the angle of projection to have a maximum range in kitti pull
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The maximum angle of the Projection for having the maximum range is 45°.
Reason ⇒ As we all know that the maximum m value of the Sine is 1 which is on 90°.
∴ From the Formula of Range,
R = u²Sin2θ/g, we must need to multiply 2 by 45° to get 90°. This can give the maximum angle for maximum range. Initial velocity can also increase to give maximum range.
Hope it helps.
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