Question

What is the angle of projection to have a maximum range in kitti pull?if one strikes kitti pull with the speed of 98 ms-1 what is the maximum range achieved

Answer 1

The angle of projection is 45° to have a maximum range .
Projected velocity=strikes velocity

maximum range = 2u²sin2©/g
=2×98×98×sin2×45°/9.8
=2×98×98×1/9.8
=2×98×10=1960m