Question

what is the angle of projection when kinetic energy and maximum height is one fourth​

Answer 1

Answer:

angle of projection must be 60° when kinetic energy at maximum height becomes one fourth.

Explanation:

K.Ef= 1/4(K.Ei)

1/2(mv^2) = 1/4(1/2mvi^2)

As vi=v cos(theta)

So,

By solving we get

theta = 60°

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