Question

what is the angle of vector 3I^+4j^ with x axis​

Answer 1

Explanation:

angle of vector is given by,

tan alpha = Ay/Ax

Here,

Ay=4 and Ax=3

so, tan alpha= 4/3

hence, alpha= tan^-1 4/3

(where, alpha = angle between x-axis and the vector )

Answer 2

 A vector is a quantity that as both magnitude and direction . So , a vector is specified by a number and it's direction .

Symbols $i$ ,$j , k$are used to indicate the direction of that vector with x , y and z axis respectively .

• The magnitude of any vector is indicated by a number and is denoted as  $A{x}$ for x axis and $A{y}$ for y axis

         Therefore ,  From the equation $3i + 4j$ , we get  

                                  $A{x}$= 3      

                                  $A{y}$=  4

• The angle of vector is given by tan∅ =    $\frac{ Ay}{Ax}$

                                     ∅ = tan^-1   $\frac{ Ay}{Ax}$

                      therefore ∅= tan^-1 ( $\frac{ 4}{3}$ )

                                           = 53.06°          

Answer : The angle of vector $3i + 4j$ with x axis is ∅= 53.06°