Question

what is the angle that the given vector i^+√3j^ makes with y axis

Answer 1

Answer:

given vector= i + $\sqrt{3}$j

now, tan$\alpha$ =  1 / $\sqrt{3}$ = 30° with positive x-axis

so with y-axis it makes an angle of 90°-30° = 60°

HOPE THE DIAGRAM BELOW HELPS :)