Question

What is the angular acceleration of minute's hand of a clock?​

Answer 1

Answer:

The Physics

s-1. The minute takes one hour = 60 s/min × 60 min = 3600 s to go around, so ω = 2π / 3600 rad. s-1 = 1.7 × 10-3 rad.

Answer 2

$\huge \mathfrak \red { \underline {Bonjour}}$

Zero

Centripetal acceleration on the other hand is non-zero, That’s the acceleration associated with the tension inside the hand itself from being spun around in a circle.

A=v2r

Where V is the linear velocity at the end of the hand and R is the radius of the clock.

V=2rπ (distance unit per hour)

Therefore the acceleration , A=4r π²

I hope it helps you .....

#Stay Safe ❤️❤️

#Be Brainly ✌️✌️