Question

What is the angular momentum of an electron in 4f orbital?

Answer 1

angular momentum=√n(n+2) h/2π
in 4f ,n= 4
=√4×6 h/2π
=√24 2π.
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Answer 2

Answer: Angular momentum of an electron present in 4f orbital is $\frac{\sqrt{3}h}{2\pi }$

Explanation: To calculate the total angular momentum of an electron, we use the formula:

$L=\sqrt{l(l+1)}\frac{h}{2\pi }$

For f-orbital, value of l = 3

Putting the value of l = 3 in above equation, we get

$L=\sqrt{3(3+1)}\frac{h}{2\pi }$

$L=\frac{\sqrt{3}h}{\pi }$

Angular momentum of an electron present in 4f orbital is $\frac{\sqrt{3}h}{2\pi }$