Question

what is the angular momentum of electron in 3s orbital and 3d orbital

Answer 1

hell... ooo!!

Expression for orbital angular momentum (L) is : 
L = √(l (l+1)) h/2π = 0 for w s electrons 

For s-orbital, l = 0 

hope this helps you....!!

Answer 2

Answer: Angular momentum for 3s will be 0 and for 3d orbital, it will be $\frac{h\sqrt{6}}{2\pi}$

Explanation:

Orbital angular momentum depends on Azimuthal Quantum number (l). This quantum number describes the shape of the orbital. For s, p, d, f orbitals, value of 'l' will be 0, 1, 2, 3 and so on respectively.

To calculate the orbital angular momentum, we use the equation:

$L=\sqrt{l(l+1)}\frac{h}{2\pi}$     .....(1)

• For 3s orbital, 'l' will be 0

Putting values in above equation, we get:

$L=\sqrt{0(0+1)}\frac{h}{2\pi}\\\\L=0$

• For 3d orbital, 'l' will be 2

Putting values in above equation, we get:

$L=\sqrt{2(2+1)}\frac{h}{2\pi}\\\\L=\frac{h\sqrt{6}}{2\pi}$

Hence, angular momentum for 3s will be 0 and for 3d orbital, it will be $\frac{h\sqrt{6}}{2\pi}$