Question

what is the angular momentum of the electron in the bohr orbit in the hydrogen atom (3/2π= 1.055× 10–³⁴ kg m²/s)​

Answer 1

Answer:

We know, mvr=n

2π

h

4.2178×10

−34

=n×

2×3.14

6.626×10

−34

∴ n=4

λ

1

=R

H

[

n

1

2

1

−

n

2

2

1

]

=109678[

3

2

1

−

4

2

1

]

λ=1.8×10

−4

cm.