Question

what is the ans for this ques?​

Answer 1

Answer:

x = 2

Step-by-step explanation:

I believe some data is missing so my assumption is seg DE is parallel to seg AB.

According to Triangle Proportionality Theorem,

If a line parallel to one side of a triangle intersects the other two sides of the triangle, then the line divides these two sides proportionally.

Therefore, $\frac{CD}{DA} = \frac{CE}{EB}$

From given, CD = x+3

DA = 8x+9

CE = x

EB = 3x+4

Substituting, $\frac{x + 3}{8x + 9} = \frac{x}{3x + 4}$

Solving, $({x + 3})({3x + 4}) = ({x})({8x + 9})$

$3x^{2} +4x+9x+12 = 8x^{2} +9x\\3x^{2} +4x+12 = 8x^{2} \\5x^{2} -4x-12 = 0\\5x^{2} -10x+6x-12 = 0\\(5x)(x-2)+(6)(x-2) = 0\\(x-2)(5x+6) = 0\\x-2 = 0 \\or \\5x+6 = 0\\x=2\\or\\x=(-6/5)$

But since x is length, and length cannot be negative, the value of x is 2.