what is the ans of distance =260m time 20 sec. find out the speed
Answers
Answer:
Given :-
Distance covered by the boy first = 260 m
Distance covered by the boy second = 300 m
Time taken by the boy first = 20 sec
Time taken by the boy second = 20 sec
To Find :-
The average speed of the boy.
Analysis :-
Firstly find the total distance covered by the boy by adding both the distances.
Then add both the time taken and find the total time.
In order to find the average speed, divide the total distance by the total time taken by the boy.
Solution :-
Total distance,
Total distance = d₁ + d₂
Substituting their values,
⇒ 260 + 300
⇒ 560 m
Total time,
Total time = t₁ + t₂
Substituting their values,
⇒ 20 + 20
⇒ 40 sec
Using the formula,
\underline{\boxed{\sf Average \ speed=\dfrac{Total \ distance \ covered}{Total \ time \ taken} }}
Average speed=
Total time taken
Total distance covered
Given that
Distance (d) = 560 m
Time (t) = 40 sec
Substituting their values,
hope this will helpful to you
⇒ s = 560/40
⇒ s = 56/4
⇒ s = 14 m/s
Therefore, the average speed of the boy is 14 m/s.
Answer:
Given :-
Distance covered by the boy first = 260 m
Distance covered by the boy second = 300 m
Time taken by the boy first = 20 sec
Time taken by the boy second = 20 sec
To Find :-
The average speed of the boy.
Analysis :-
Firstly find the total distance covered by the boy by adding both the distances.
Then add both the time taken and find the total time.
In order to find the average speed, divide the total distance by the total time taken by the boy.
Solution :-
Total distance,
Total distance = d₁ + d₂
Substituting their values,
⇒ 260 + 300
⇒ 560 m
Total time,
Total time = t₁ + t₂
Substituting their values,
⇒ 20 + 20
⇒ 40 sec
Using the formula,
Average speed=
Total time taken
Total distance covered
Given that
Distance (d) = 560 m
Time (t) = 40 sec
Substituting their values,
⇒ s = 560/40
⇒ s = 56/4
⇒ s = 14 m/s
Therefore, the average speed of the boy is 14 m/s.