Question

what is the ans of this question .. (9 class que chapter 1st. number system) ​

Answer 1

rationalise this

you get =(3+root2)^2/7

= (9 +2+6root2)/7

=(11+6root2)/7

a= 11/7 and b =6/7

Answer 2

$\frac{3 + \sqrt{2} }{3 - \sqrt{2} } \times \frac{3 + \sqrt{2} }{3 + \sqrt{2} }$

$= > \frac{(3 + \sqrt{2} )^{2} }{ {3}^{2} - {( \sqrt{2)} }^{2} }$

$= > \frac{9 + 6 \sqrt{2} + 2 }{9 - 2}$

$= > \frac{11 + 6 \sqrt{2} }{7}$

$= > \frac{11}{7} + \frac{6 \sqrt{2} }{7}$

$hence \: \: a = \frac{11}{7} b = \frac{6}{7}$