Question

what is the answer? ​

Answer 1

Answer:

weight of substance = 10.6 g

molecular weight of Na2CO3 =106 g/mol

volume = 500 ml.

Now, Molarity can be find by using the formula

$M \: = \frac{given \: mass}{ molar \: mass} \times \frac{1000}{volume \: in \: ml}$

$M = \frac{10.6}{106} \times \frac{1000}{500}$

$M = 0.2M \:$

so, 0.2 M option (a) is the correct answer.