Question

what is the answer?​

Answer 1

Hope it helps....

Please mark as brainliest........

Answer 2

Answer:

${b}^{2}$

Step-by-step explanation:

$if \: x = b \cos( \alpha ) \: \: \: y = b \sin( \alpha )$

$now \: \: {x}^{2} + {y}^{2} \\ = {(b \cos( \alpha ) )}^{2} + {(b \sin( \alpha ) )}^{2} \\ = {b}^{2} {( \cos( \alpha )) }^{2} + {b}^{2} {( \sin( \alpha )) }^{2} \\ = {b}^{2}$