Question

what is the answer ​

Answer 1

Answer:

Using delta star conversion for ABC & CDF, hence each resistance will be (2/3)Ω Hence (2/3) + 2 + (2/3) = (4/3) + 2 = (10 / 3)Ω also (2/3) + 2 + (2/3) = (10 / 3)Ω

hence

Equivalent R = (2/3) + (2/3) + [(10/3) || (10/3)] = (4/3) + (5/3) = 3Ω  ∴ I = (3/R) = (3/3) = 1A

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