Question

what is the answer ??​

Answer 1

In a quadratic equation 2++=0
a
x
2
+
b
x
+
c
=
0
the sum of the solutions (if any) is equal to −/
−
b
/
a
. In fact, if 1
x
1
and 2
x
2
are the solutions then
2++=(−1)(−2)=2−(1+2)+(1⋅2)
a
x
2
+
b
x
+
c
=
a
(
x
−
x
1
)
(
x
−
x
2
)
=
a
x
2
−
a
(
x
1
+
x
2
)
x
+
a
(
x
1
⋅
x
2
)
and by comparing the coefficients we get 1+2=−/
x
1
+
x
2
=
−
b
/
a
.

In your case 1+2=2(3−1)
x
1
+
x
2
=
2
(
3
m
−
1
)
. It seems that the sum of the (complex) solutions is −1
−
1
if =1/6
m
=
1
/
6
.

Answer 2

Answer:

Hope this helped you...