what is the answer ???
Answers
Answer:
a. Speed does not have direction (scalar quantity). So, steepest slope is answer. Thus, the particle has maximum speed in the time interval between -1 seconds and 1 seconds.
b. Average Velocity = (Final Displacement - Initial Displacement)/(Final Time - Initial time)
= (-1m - (+1m))/(5s - (-5s)) = -2m/10s = -1/5 m/s
c. Average Speed = Total Distance/Total Time
= (2m + 1m + 8m + 2m + 1m)/(5 -(-5))s [No negative distance, as it is a scalar quantity]
= 14m/10s = 1.4 m/s
d. Velocity = Displacement/time
Velocity in 2s to 3s = (2m - (-4m))/(3s - 2s)
= 2m/1s = 2m/s
Velocity in 3s to 4s = (-1m - (-2m))/(4s - 3s)
= 1m/1s = 1m/s
Ratio = 2:1
e. When there is no change in the coordinate of x(t) axis (displacement), the displacement is 0 in that time interval. Velocity = Displacement/time = 0/time = 0 m/s. Thus, velocity is 0 in -5s to -4s interval, and also in 4s to 5s interval.