what is the answer ????
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This is just a trick
Sp = 2 sigma bonds
sp2 = 3 sigma bonds
Sp3 = 4 sigma bonds
Therefore,
In central atom (=c=) as there are 2 sigma bonds and 2 pi bonds hybridisation is SP
Similarly hybridisation of terminal carbon is sp2
Sp = 2 sigma bonds
sp2 = 3 sigma bonds
Sp3 = 4 sigma bonds
Therefore,
In central atom (=c=) as there are 2 sigma bonds and 2 pi bonds hybridisation is SP
Similarly hybridisation of terminal carbon is sp2
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