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Angle AOB = ?
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As we are given that angle APB is 60° .
We know that the radius is perpendicular to the tangents so Angle PAO and Angle PBO becomes 90° .
So , by angle sum property of a quadrilateral we know that
So , by angle sum property of a quadrilateral we know that Angle PBO+Angle PAO+Angle APB+ Angle AOB = 360°
solving it,
Angle PBO+Angle PAO+Angle APB+ Angle AOB = 360°
90°+90°+60°+Angle AOB = 360°
180°+60°+Angle AOB = 360°
240° + Angle AOB= 360°
Angle AOB = 360°-240°
Angle AOB= 120°
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angle AOB will be of 120° .............
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