Question

what is the answer dear's ....​

Answer 1

Answer:

Answer

Given triangle PQR, PR>PQ and PS bisects ∠QPR

In ΔPQR

PR>PQ ....(Given )

∴∠PQR>∠PRQ (Angle opposite side of the longer side is greater)

In ΔPQS and RPS

∠PQR=∠PQS=180−(∠PSQ+∠QPS)

∠PRQ=∠PRS=180−(∠PSR+∠RPS)

Given PS is bisector of ∠QPR

Then ∠QPS=∠PRQ

∠PQR>∠PRQ

∴180−(∠PSQ+∠QPS)>180−(∠PSR+∠RPS) ( ∠QPS=∠PRQ)

⇒∠PSQ>∠PSR

Step-by-step explanation:

i hope its help as

Answer 2

Answer:

See the attachment for your answer