Question

what is the answer dears...?​

Answer 1

ᴏᴋ ɴᴏᴡ ɪ ʜᴀᴠᴇ ᴛᴏ ʀᴇᴀᴄʜ ᴍʏ ᴄᴏʟʟᴇɢᴇ ɪ ᴡɪʟʟ ʜᴇʟᴘ ʏᴏᴜ sᴏᴏɴ

Answer 2

SOLUTION :-

We have ,

In triangle ▲ACE and ▲ABD;

∠ADB = ∠AEC (since right angled)

∠BAC = ∠CAB (common)

AB = AC (given)

Therefore ▲ACE ≅ ▲ABD by AAS congruence criterion

So, BD = EC (c.p.c.t)

NOTE

Here 'c.p.c.t' means congruent part of congruent traingle