What is the answer dears ....pls help me
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Given ABC is a triangle in which altitudes BD and CE to sides AC and AB are equal
In ΔADB and ΔACE
∠ADB=∠AEC=90
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(altitudes BD and CE to sides AC and AB)
BD=CE (Given altitudes are equal)
∠BAD=∠DAB (Common angle )
ΔABD≅ΔACE [by SAS congruence]
So AB=AC
Then triangle ABC is an isosceles triangle
Step-by-step explanation:
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