Question

what is the answer for a rectangle having length 10 cm and breadth 14 centimetre its perimeter is​

Answer 1

Answer:

• The Perimeter of rectangle = 28 cm.

Given :

• Length of rectangle = 10 cm

• Breadth of rectangle = 14 cm

To find :

• Perimeter of rectangle =?

Step-by-step explanation :

Perimeter of rectangle = 2(Length+Breadth)

Substituting the values in the above formula, we get,

→ 2( 10 + 14)

→ 2 (24)

→ 2 × 24

→ 48

Thus, The Perimeter of rectangle = 48 cm.

Answer 2

Answer:

$\large{\underline{\boxed{\mathfrak\blue{Perimeter \: of \: rectangle = 48 \: cm }}}}$

Correct Question:-

A rectangle having length of 14 cm and breadth of 10 cm.What is the value of the perimeter of rectangle?

†Reference of diagram given below:-

$\setlength{\unitlength}{0.78 cm}\begin{picture}(12,4)\thicklines\put(5.6,9.1){ A }\put(5.5,5.8){ B }\put(11.1,5.8){ C }\put(11.05,9.1){ D }\put(4.5,7.5){ 10\:cm }\put(8.1,5.3){ 14\:cm }\put(11.5,7.5){ 10 \:cm }\put(8.1,9.5){ 14\:cm }\put(6,6){\line(1,0){5}}\put(6,9){\line(1,0){5}}\put(11,9){\line(0,-1){3}}\put(6,6){\line(0,1){3}}\end{picture}$

Given:-

• Length = 14 cm
• Breadth = 10 cm

To find:-

• Perimeter of rectangle = ?

$\rm We \: know, \\\\\star{\boxed{\rm{Perimeter_{rectangle} = 2(length + breadth)}}}$

$\scriptsize \: \: \: \: \: \: \: \: \: \dag\sf\green{Putting \: values:- }$

⇒Perimeter = 2(14 + 10) cm

⇒Perimeter = (2 × 24) cm

⇒Perimeter = 48 cm

$\therefore{\underline{\text{Perimeter \: of \: rectangle = 48 \: cm. }}}$

$\rule{200}{1}$

More informations about a rectangle:-

⇒ $\sf Area \: of \: rectangle = Length \times Breadth$

⇒ $\sf Diagonal_{rectangle}= \sqrt{(l^2 + b^2}$

⇒ $\sf Cost \: of \: fencing = Perimeter \times Rate_{fencing}$

⇒ $\sf Cost \: of \: flooring = Area \times Rate_{flooring}$