Question

what is the answer for factorize 1/64 x^3 - 8y^3 + 3/16 x^2y - 3/2xy^2”

Answer 1

Answer:(1/8x - 2y)^3

Step-by-step explanation:

1/64x^3 = ( 1/8x)^3

-8y^3 = -(2y)^3

3/16x^2y = 3 ×(1/8x)^2×2y

3/2x^2y = 3×(1/8x)× (2y)^2

1/64x^3-8y^3+3/16x^2y-3/2xy^2 = (1/8x-2y)^3 #(a-b)^3 identity

Answer 2

hope this will help you

mark it as brainlist answer please