what is the answer for that question
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sol. we know ,
horizontal range = u²sin2Ф/g
maximum height = u²sin²Ф/2g
A/C to question,
horizontal range = 3× maximum height
u²sin2Ф/g = 3 × u² sin²Ф/2g
{ sin2Ф = 2sinФ.cosФ }
2sinФ.cosФ = 3/2. sin²Ф
tanФ = 4/3
Ф = tan⁻¹(4/3)
Read more on Brainly.in - https://brainly.in/question/1299770#readmore
horizontal range = u²sin2Ф/g
maximum height = u²sin²Ф/2g
A/C to question,
horizontal range = 3× maximum height
u²sin2Ф/g = 3 × u² sin²Ф/2g
{ sin2Ф = 2sinФ.cosФ }
2sinФ.cosФ = 3/2. sin²Ф
tanФ = 4/3
Ф = tan⁻¹(4/3)
Read more on Brainly.in - https://brainly.in/question/1299770#readmore
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