what is the answer for this ???
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see Here..
AngleDBF=180°-60°=120°(linear Pair.)
Angle CAE=AngleDBF(Corresponding Angles)
→angle CAE=120°
Angle CAE+AngleCAB +x= 360° ( Since C,E,B are Rays With Same Inital point A)
→360°= 120°+130°+x
→360°-250°=x
→x=110°
Hope it Helps...
Regards,
Leukonov.
AngleDBF=180°-60°=120°(linear Pair.)
Angle CAE=AngleDBF(Corresponding Angles)
→angle CAE=120°
Angle CAE+AngleCAB +x= 360° ( Since C,E,B are Rays With Same Inital point A)
→360°= 120°+130°+x
→360°-250°=x
→x=110°
Hope it Helps...
Regards,
Leukonov.
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erpendicular tringle
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