Question

what is the answer for this question​

Answer 1

Answer:

= )) (sin²A cos²B) + (cos²A sin²B )+ (sin²A sin²B) +( cos²A cos²B )

=)) ( sin²A cos²B )+ (cos²A cos²B) +

( cos²A sin²B) + ( sin²A sin²B)

=)) cos²B (sin²A + cos²A)

+ sin²B ( cos²A + sin²A)

=)) cos²B (1) + sin²B (1)

=)) cos²B + sin²B

=)) sin²B + cos ² B

=)) 1

therefor, (sin²A cos²B) + (cos²A sin²B )+ (sin²A sin²B) +( cos²A cos²B ) = 1

formula used =>> sin²Φ + cos²Φ = 1