what is the answer for this question. ..write it in detail
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Answered by
1
here angleBCD=angleADC
and angleACB= angleBDA
THEN
angleACD=angleBDC
and both triangles have same base
TRIANGLES WITH SAME BASE AND ONE ANGLE
WE KNOW THAT
SIDES OPPOSITE TO EQUAL ANGLES ARE EQUAL
AD IS OPPOSITE TO ANGLE ACD
AND BC IS OPPOSITE TO ANGLE BDC
SO
AD=BC
and angleACB= angleBDA
THEN
angleACD=angleBDC
and both triangles have same base
TRIANGLES WITH SAME BASE AND ONE ANGLE
WE KNOW THAT
SIDES OPPOSITE TO EQUAL ANGLES ARE EQUAL
AD IS OPPOSITE TO ANGLE ACD
AND BC IS OPPOSITE TO ANGLE BDC
SO
AD=BC
Answered by
0
angle BCD=angle ADC -(1)
angle ACB=angle BDA -(2)
adding 1 and 2
angle ACD=angle BDC or angle C=angle D
in triangle ACD & BDC
angle C=angle D
angle BCD = angle ADC (given)
CD=CD (common)
therefore,triangle ACD congruent to triangle BDC
by CPCT, AD = BC proved
angle ACB=angle BDA -(2)
adding 1 and 2
angle ACD=angle BDC or angle C=angle D
in triangle ACD & BDC
angle C=angle D
angle BCD = angle ADC (given)
CD=CD (common)
therefore,triangle ACD congruent to triangle BDC
by CPCT, AD = BC proved
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