Math, asked by pragathi1133, 10 months ago

what is the answer for this questions

did you answer for this all questions with in 5.30 l will you big price​

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Answered by pulakmath007
24

Answer:

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Step-by-step explanation:

The answers are :

10. IV

11. IV

12. I

13. II

14. IV

15. I

Answered by Yuseong
432

Question:

10. Which of the following is the reciprocal of the reciprocal of a rational number?

i) - 1  \qquad ii) 1

iii) 0  \qquad iv) The number itself

Solution:

Here, we are asked that what will be the reciprocal of the reciprocal of a rational number.

Now, if we have already reciprocal of a number and we have to reciprocate it, so that number will be the number itself.

➳ Let's understand with an example.

 \rm {\dfrac{1}{9}} is the reciprocal of 9, now if we are asked to find the reciprocal of  \rm {\dfrac{1}{9}} then the answer will be 9 ( the number itself) .

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Question:

Between two given rational numbers, we can find

  • I) One and only rational number.
  • ii) only two rational numbers
  • iii) only ten rational numbers
  • iv) Infinitely many rational numbers

Solution:

➳ There exists infinite rational numbers between two rational number, so we can find infinitely many rational numbers between two rational numbers.

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Question:

 \sf {\dfrac {x+y}{2}} is a rational number

  • i) between x and y
  • ii) less than x and y both
  • iii) greater than x and y both
  • iv) less than x but greater than y

Solution:

This is the method by which we can find a rational number between two rational number.

➳ Let's understand with an example.

Example Question,

  • Find 1 rational number between 8 and 6 ( We know the answer is 7, but we have to find it by this formula.)

So, x= 8 and y = 6

 \sf {  \dfrac{x + y}{2}  =  \dfrac{8 + 6}{2}  = \cancel{ \dfrac{14}{2} } = 7}

So, from this example we easily understood that this formula is used to find a rational number between x any y.

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Question:

 \large \rm { - (-x)} is same as

  •  \large \rm { -x}
  •  \large \rm { x} (Correct answer)
  •  \large \rm { \dfrac{1}{x}}
  •  \large \rm { \dfrac{21}{8}}

Answer:

In this question we have to open the bracket to find the correct value,

So, we know that  \large \rm {( -) \times (-) is (+) }

 \large \rm {\therefore - (-x) = +x \: or \: x}

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Question :

The multiplicative inverse of  \sf { - 1 \dfrac{1}{7}} is

  •  \large \rm { \dfrac{8}{7}}
  •  \large \rm {- \dfrac{8}{7}}
  •  \large \rm { \dfrac{7}{8}}
  •  \large \rm {- \dfrac{7}{8}} (correct answer)

Solution:

So here in the question, we can write  \sf { - 1 \dfrac{1}{7}} as  \sf {- \dfrac{8}{7}}

Now, the multiplicative inverse of  \sf {- \dfrac{8}{7}} is  \sf {- \dfrac{7}{8}}

So, the answer is  \sf {- \dfrac{7}{8}}.

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Question:

The additive inverse of  \sf { - 1 \dfrac{1}{7}} is

  •  \large \rm { \dfrac{8}{7}} (Correct answer)
  •  \large \rm {- \dfrac{8}{7}}
  •  \large \rm { \dfrac{7}{8}}
  •  \large \rm {- \dfrac{7}{8}}

Solution:

Now here in the question we have to find the additive inverse of  \sf { - 1 \dfrac{1}{7}}.

So here, we can write  \sf { - 1 \dfrac{1}{7}} as  \sf {- \dfrac{8}{7}}.

And,

Now, the additive inverse of  \sf {- \dfrac{8}{7}} is  \sf { \dfrac{8}{7}}.

So, the answer is \sf { \dfrac{8}{7}}

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