Question

what is the answer ?
full method should be done plz​

Answer 1

Answer:

$\huge{ \mathfrak{ \underline{Given}}}$

1) 5x + 9 = 2 x - 12

$\huge{\bf{\underline{\red{Solution:}}}}$

★Simplifying

5x + -9 = 2x + 12

★Reorder the terms:

-9 + 5x = 2x + 12

★Reorder the terms:

-9 + 5x = 12 + 2x

Solving:

-9 + 5x = 12 + 2x

Solving for variable $\boxed{\pink{“ x ” }}$

Move all terms containing x to the left, all other terms to the right.

Add $\boxed{\pink{“ -2x ” }}$ to each side of the equation.

-9 + 5x + -2x = 12 + 2x + -2x

★Combine like terms: 5x + -2x = 3x

-9 + 3x = 12 + 2x + -2x

★Combine like terms: 2x + -2x = 0

-9 + 3x = 12 + 0

-9 + 3x = 12

★Add $\boxed{\pink{“ 9 ” }}$ to each side of the equation.

-9 + 9 + 3x = 12 + 9

★Combine like terms: -9 + 9 = 0

0 + 3x = 12 + 9

3x = 12 + 9

★Combine like terms: 12 + 9 = 21

3x = 21

★Divide each side by '3'.

x = 7

★Simplifying

$\huge{\bf{\underline{\red{Answer :}}}}$

$\boxed{\pink{x = 7 }}$

2) 3 (x + 10) = 14.

3 (x + 10) = 14

3x + 30 = 14

★Subtract 30 from both sides of the equation:

3x + 30 = 14

3x + 30 - 30 = 14 - 30

★Subtract the members

3x + 30 - 30 = 14 - 30

3x = 14 - 30

★Subtract the numbers

3x = 14 - 30

3x = -16

★Divide both side of the equation by the same term

3x = -16

$\large \frac{3x}{3} = \frac{ - 16}{6}$

★Cancel term term that are in Both the numerator and denominator

$\large \frac{3x}{3} = \frac{ - 16}{6}$

$\large x = \frac{ - 16}{ 3}$

$\huge{\bf{\underline{\red{Answer :}}}}$

$\large x = \frac{ - 16}{ 3}$

Answer 2

$\Huge\mathfrak\blue{an{\mathcal{S}}wer:}$

${ }$

$\large\bf{{\underline{To~simplify}}:}$

$\bf (1) \: \: \: 5x + 9 = 2x - 12 \\ \tt : \longmapsto 5x - 2x = - 12 - 9 \\ \tt : \longmapsto 3x = - 21 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \tt : \longmapsto x = \frac{ - 21}{3} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \tt : \longmapsto x = \blue{ \underline{ \boxed{ \bf - 7}}}\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

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$\bf (2) \: \: \: 3(x + 10) = 14 \\ \tt : \longmapsto 3x + 30 = 14 \: \: \: \: \: \: \\ \tt : \longmapsto 3x = 14 - 30 \: \: \: \: \: \: \\ \tt : \longmapsto 3x = - 16 \: \: \: \: \: \: \: \: \: \: \: \: \\ \tt : \longmapsto x = \blue{ \underline{ \boxed{ \bf \: \frac{ - 16}{3} \: }}} \: \: \: \: \: \: \: \:$