what is the answer in the question in the options
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Answered by
1
Answer:
the correct option is 4th option
Step-by-step explanation:
when we expand the determinant we get
x(6x-6x)-(x^2)(12-(x^2))+x(12-(x^2))
x(0)-12(x^2)+(x^4)+12x-(x^3)
(x^4)-(x^3)-12(x^2)+12x
then compare the co-efficients of given determinant equation
then a=1 , b=-1 , c=-12 , d=12 , e=0
then
=5(1)+4(-1)+3(-12)+2(12)+0
=5-4-36+24
=29-40
=-11
Answered by
33
First solve the determinant . we get,
compare it with
Ax^4+Bx^3+cx^2+Dx+E
we get ,
A=1
B=-1
C=-12
D=12
and
E= 0
Now to find :
◆5A+4B+3C+2D+E
PUT THE VALUES
= 5(1)+4(-1)+3(-12)+2(12)+0
=5-4-36+24
=29-40
=-11
Soln refers to the attachment..
Option 4 is correct.
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