Question

what is the answer in the question in the options​

Answer 1

Answer:

the correct option is 4th option

Step-by-step explanation:

when we expand the determinant we get

x(6x-6x)-(x^2)(12-(x^2))+x(12-(x^2))

x(0)-12(x^2)+(x^4)+12x-(x^3)

(x^4)-(x^3)-12(x^2)+12x

then compare the co-efficients of given determinant equation

then a=1 , b=-1 , c=-12 , d=12 , e=0

then

=5(1)+4(-1)+3(-12)+2(12)+0

=5-4-36+24

=29-40

=-11

Answer 2

First solve the determinant . we get,

${x}^{4} - {x}^{3} - 12 {x}^{2} - 12x$

compare it with

Ax^4+Bx^3+cx^2+Dx+E

we get ,

A=1

B=-1

C=-12

D=12

and

E= 0

Now to find :

◆5A+4B+3C+2D+E

PUT THE VALUES

= 5(1)+4(-1)+3(-12)+2(12)+0

=5-4-36+24

=29-40

=-11

Soln refers to the attachment..

$\huge\boxed{ \green{\bold{- 11}}}$

Option 4 is correct.